中二(公式)

更新1:

唔好意思，第二题因该系 pq/p^2q-pq^2

8a^2b/12ab^3c^2 = 4ab(2a)/(4ab * 3b^2c^2) = 2a/(3b^2c^2) pq/p^2q-pq^2 = pq/[pq (p - q)] = 1/(p-q) y+2/3y+6 = (y+2)/[3(y+2)] = 1/3 使x成为公式y=mx+c的主项。 y = mx + c => y - c = mx + c - c .......... 两边各减 c => y - c = mx => mx = y - c .......... 左右互换 => mx/m = (y - c)/m .......... 两边各除 m => x = (y - c)/m 使B成为公式A=2B/B+C的主项。 A = 2B/(B+C) => A(B+C) = 2B/(B+C) * (B+C) .......... 两边各 * (B+C) => A(B+C) = 2B => AB + AC = 2B => AC = 2B - AB => AC = B(2 - A) => B = AC/(2 - A) 使a成为公式2n/a+n/b=4的主项。 2n/a + n/b = 4 => 2n/a = 4 - n/b => 2n/a = (4b-n)/b => 2n/a * ab = (4b-n)/b * ab .......... 两边各*ab => 2bn = (4b-n)a => a(4b-n) = 2bn => a = 2bn/(4b-n) 使y成为公式6a/x-2a/y=1的主项。 6a/x - 2a/y = 1 => 6a/x - 1 = 2a/y => (6a/x - 1) xy = 2a/y * xy .......... 两边各*xy => 6ay - xy = 2ax => 6ay - 2ax = xy =>2a(3y - x) = xy => a = xy/[2(3y-x)]
8a^2b/12ab^3c^2 =2a/3b^2c^2 第2条唔系太明个题目 y+2/3y+6 =1/3 x=(y-c)/m B=-(AC/A-2) a=2bn/(4b-n) y=-2ax/(x-6a)
参考: 自己

更新1:

唔好意思，第二题因该系 pq/p^2q-pq^2

8a^2b/12ab^3c^2 = 4ab(2a)/(4ab * 3b^2c^2) = 2a/(3b^2c^2) pq/p^2q-pq^2 = pq/[pq (p - q)] = 1/(p-q) y+2/3y+6 = (y+2)/[3(y+2)] = 1/3 使x成为公式y=mx+c的主项。 y = mx + c => y - c = mx + c - c .......... 两边各减 c => y - c = mx => mx = y - c .......... 左右互换 => mx/m = (y - c)/m .......... 两边各除 m => x = (y - c)/m 使B成为公式A=2B/B+C的主项。 A = 2B/(B+C) => A(B+C) = 2B/(B+C) * (B+C) .......... 两边各 * (B+C) => A(B+C) = 2B => AB + AC = 2B => AC = 2B - AB => AC = B(2 - A) => B = AC/(2 - A) 使a成为公式2n/a+n/b=4的主项。 2n/a + n/b = 4 => 2n/a = 4 - n/b => 2n/a = (4b-n)/b => 2n/a * ab = (4b-n)/b * ab .......... 两边各*ab => 2bn = (4b-n)a => a(4b-n) = 2bn => a = 2bn/(4b-n) 使y成为公式6a/x-2a/y=1的主项。 6a/x - 2a/y = 1 => 6a/x - 1 = 2a/y => (6a/x - 1) xy = 2a/y * xy .......... 两边各*xy => 6ay - xy = 2ax => 6ay - 2ax = xy =>2a(3y - x) = xy => a = xy/[2(3y-x)]
8a^2b/12ab^3c^2 =2a/3b^2c^2 第2条唔系太明个题目 y+2/3y+6 =1/3 x=(y-c)/m B=-(AC/A-2) a=2bn/(4b-n) y=-2ax/(x-6a)
参考: 自己

更新1:

唔好意思，第二题因该系 pq/p^2q-pq^2

8a^2b/12ab^3c^2 = 4ab(2a)/(4ab * 3b^2c^2) = 2a/(3b^2c^2) pq/p^2q-pq^2 = pq/[pq (p - q)] = 1/(p-q) y+2/3y+6 = (y+2)/[3(y+2)] = 1/3 使x成为公式y=mx+c的主项。 y = mx + c => y - c = mx + c - c .......... 两边各减 c => y - c = mx => mx = y - c .......... 左右互换 => mx/m = (y - c)/m .......... 两边各除 m => x = (y - c)/m 使B成为公式A=2B/B+C的主项。 A = 2B/(B+C) => A(B+C) = 2B/(B+C) * (B+C) .......... 两边各 * (B+C) => A(B+C) = 2B => AB + AC = 2B => AC = 2B - AB => AC = B(2 - A) => B = AC/(2 - A) 使a成为公式2n/a+n/b=4的主项。 2n/a + n/b = 4 => 2n/a = 4 - n/b => 2n/a = (4b-n)/b => 2n/a * ab = (4b-n)/b * ab .......... 两边各*ab => 2bn = (4b-n)a => a(4b-n) = 2bn => a = 2bn/(4b-n) 使y成为公式6a/x-2a/y=1的主项。 6a/x - 2a/y = 1 => 6a/x - 1 = 2a/y => (6a/x - 1) xy = 2a/y * xy .......... 两边各*xy => 6ay - xy = 2ax => 6ay - 2ax = xy =>2a(3y - x) = xy => a = xy/[2(3y-x)]
8a^2b/12ab^3c^2 =2a/3b^2c^2 第2条唔系太明个题目 y+2/3y+6 =1/3 x=(y-c)/m B=-(AC/A-2) a=2bn/(4b-n) y=-2ax/(x-6a)
参考: 自己

更新1:

唔好意思，第二题因该系 pq/p^2q-pq^2

8a^2b/12ab^3c^2 = 4ab(2a)/(4ab * 3b^2c^2) = 2a/(3b^2c^2) pq/p^2q-pq^2 = pq/[pq (p - q)] = 1/(p-q) y+2/3y+6 = (y+2)/[3(y+2)] = 1/3 使x成为公式y=mx+c的主项。 y = mx + c => y - c = mx + c - c .......... 两边各减 c => y - c = mx => mx = y - c .......... 左右互换 => mx/m = (y - c)/m .......... 两边各除 m => x = (y - c)/m 使B成为公式A=2B/B+C的主项。 A = 2B/(B+C) => A(B+C) = 2B/(B+C) * (B+C) .......... 两边各 * (B+C) => A(B+C) = 2B => AB + AC = 2B => AC = 2B - AB => AC = B(2 - A) => B = AC/(2 - A) 使a成为公式2n/a+n/b=4的主项。 2n/a + n/b = 4 => 2n/a = 4 - n/b => 2n/a = (4b-n)/b => 2n/a * ab = (4b-n)/b * ab .......... 两边各*ab => 2bn = (4b-n)a => a(4b-n) = 2bn => a = 2bn/(4b-n) 使y成为公式6a/x-2a/y=1的主项。 6a/x - 2a/y = 1 => 6a/x - 1 = 2a/y => (6a/x - 1) xy = 2a/y * xy .......... 两边各*xy => 6ay - xy = 2ax => 6ay - 2ax = xy =>2a(3y - x) = xy => a = xy/[2(3y-x)]
8a^2b/12ab^3c^2 =2a/3b^2c^2 第2条唔系太明个题目 y+2/3y+6 =1/3 x=(y-c)/m B=-(AC/A-2) a=2bn/(4b-n) y=-2ax/(x-6a)
参考: 自己

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